Posts filed under 'Atomic Electron Confuguration'
ChemistryTutorSite - Homework Chemistry Help
What are the group trends for ionic radius?
ChemistryTutorSite - Homework Chemistry Answer
to answer this question i well give you example of the group IA the electron configuration of all atoms in this group are:
H 1s1
Li [He]2s1
Na [Ne]3s1
K [Ar]4s1
Rb [Kr]5s1
Cs [Xe]6s1
Fr [Rn]7s1
from H to Fr there are extra layers or sub shell that we add to the atoms thus from H to Fr or down to the group the atomic radius will be greater.
if they form ion the group IA will be release 1 electron each so the electron configuration will be:
H 1s0
Li [He]
Na [Ne]
K [Ar]
Rb [Kr]
Cs [Xe]
Fr [Rn]
the atomic radius of a metal is generally larger than the ionic radius of the same element for the example the radius of Na will be greater than Na+.
But if we go down in the same group they still have the same trend of radius with the atomic radius thus for the ionic radius in the same group the ionic radius will be greater if we go down in the same group.
December 2nd, 2008
Chemistry Tutor Site-Problem
How can I determine the number of valence electrons for an element?
Chemistry Tutor Site-Answer
That is simple- Just write down the the electronic configuration of the atomic number of that element. And the number of electrons in the last shell are the valence electrons.
For eg: Na(Sodium) has the atomic number 11, now there are four shells in which the distribustion takes place- namely- K,L,M,N.These shells are also known as energy levels.
The max no of electrons in K is 2, In L is 8, M is 16 and finally in N its 32.
And you cant fill the next shell till the total number is completed in one shell.
There fore for Na the configuration is: K= 2 L= 8 M= 1
And hence the valence electron is 1. That is only one electron partcipates in bond formation and in chemical reactions.
October 14th, 2008
Chemistry Tutor Site-Problem
How can I determine the number of valence electrons for an element?
Chemistry Tutor Site-Answer
That is simple- Just write down the the electronic configuration of the atomic number of that element. And the number of electrons in the last shell are the valence electrons.
For eg: Na(Sodium) has the atomic number 11, now there are four shells in which the distribustion takes place- namely- K,L,M,N.These shells are also known as energy levels.
The max no of electrons in K is 2, In L is 8, M is 16 and finally in N its 32.
And you cant fill the next shell till the total number is completed in one shell.
There fore for Na the configuration is: K= 2 L= 8 M= 1
And hence the valence electron is 1. That is only one electron partcipates in bond formation and in chemical reactions.
October 14th, 2008
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