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	<title>Comments on: Use The Oxidation Number Method To Balance The Following Redox Equations.?</title>
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		<title>By: Timi</title>
		<link>http://www.chemistrytutorsite.com/2009/05/12/use-the-oxidation-number-method-to-balance-the-following-redox-equations/comment-page-1/#comment-1448</link>
		<dc:creator>Timi</dc:creator>
		<pubDate>Wed, 13 May 2009 04:58:35 +0000</pubDate>
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		<description>Zn + 4 HNO3 ----&gt; Zn(NO3)2 + 2 NO2 (g) + 2 H2O
oxidation numbers(left side): Zn: 0, H: +1, O: -2, N: +5,
oxidation numbers (right side) : Zn: +2, N(in HNO3): +5, O: -2, N(in NO2): +4 
Zn: 0 =&gt; +2      (+2)          &#124;  *1
N: +5=&gt; +4       (-1)           &#124;  *2
3Cu+ 8HNO3----&gt; 3Cu(NO3)2 + 2NO +4H2O
oxidation numbers(left side): Cu: 0, H: +1, O: -2, N: +5
oxidation numbers (right side) : Cu: +2, N(in HNO3): +5, O: -2, N(in NO): +2
Cu: 0 =&gt; +2    (+2)     &#124;*3
N: +5 =&gt; +2    (-3)      &#124;*2</description>
		<content:encoded><![CDATA[<p>Zn + 4 HNO3 &#8212;-> Zn(NO3)2 + 2 NO2 (g) + 2 H2O<br />
oxidation numbers(left side): Zn: 0, H: +1, O: -2, N: +5,<br />
oxidation numbers (right side) : Zn: +2, N(in HNO3): +5, O: -2, N(in NO2): +4<br />
Zn: 0 => +2      (+2)          |  *1<br />
N: +5=> +4       (-1)           |  *2<br />
3Cu+ 8HNO3&#8212;-> 3Cu(NO3)2 + 2NO +4H2O<br />
oxidation numbers(left side): Cu: 0, H: +1, O: -2, N: +5<br />
oxidation numbers (right side) : Cu: +2, N(in HNO3): +5, O: -2, N(in NO): +2<br />
Cu: 0 => +2    (+2)     |*3<br />
N: +5 => +2    (-3)      |*2</p>
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