http://www.chemistrytutorsite.com/2009/05/12/in-which-of-the-followong-does-an-element-have-an-oxidation-number-of-4/ Chemistry Tutor Site--Your Free Chemistry Tutor Site Fri, 30 Jul 2010 08:32:27 +0000 http://wordpress.org/?v=2.7 hourly 1 http://www.chemistrytutorsite.com/2009/05/12/in-which-of-the-followong-does-an-element-have-an-oxidation-number-of-4/comment-page-1/#comment-1442 skipper Tue, 12 May 2009 18:44:56 +0000 http://www.chemistrytutorsite.com/?p=661#comment-1442 TiO2 O = -2 2O = 2x-2 = -4 Ti = +4 HBr: Br=-1 so H = +1 SO3: O = -2 so 3O = -6 and S = +6 SO4-2: 4x-2 = -8 and S = +6 because SO4=-2 TiO2
O = -2
2O = 2x-2 = -4
Ti = +4
HBr: Br=-1 so H = +1
SO3: O = -2 so 3O = -6 and S = +6
SO4-2: 4x-2 = -8 and S = +6 because SO4=-2

]]> http://www.chemistrytutorsite.com/2009/05/12/in-which-of-the-followong-does-an-element-have-an-oxidation-number-of-4/comment-page-1/#comment-1443 Anonymous Tue, 12 May 2009 18:44:56 +0000 http://www.chemistrytutorsite.com/?p=661#comment-1443 Only titanium dioxide. Oxygen is almost always -2, and that is the case in both of the sulfur compounds. The last formula is wrong; it should be SO4--. Only titanium dioxide. Oxygen is almost always -2, and that is the case in both of the sulfur compounds. The last formula is wrong; it should be SO4–.

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