In Which Of The Followong Does An Element Have An Oxidation Number Of +4?
May 12th, 2009
TiO2
HBr
SO3
SO4-
All numbers are subscript. Please explain how you got the answer. Thanks!
Entry Filed under: Chemical Equation
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2 Comments Add your own
1. skipper | May 12th, 2009 at 12:44 pm
TiO2
O = -2
2O = 2x-2 = -4
Ti = +4
HBr: Br=-1 so H = +1
SO3: O = -2 so 3O = -6 and S = +6
SO4-2: 4x-2 = -8 and S = +6 because SO4=-2
2. Anonymous | May 12th, 2009 at 12:44 pm
Only titanium dioxide. Oxygen is almost always -2, and that is the case in both of the sulfur compounds. The last formula is wrong; it should be SO4–.
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