Calculate M for the MF2 That Produce from The Reaction of M and F2
December 2nd, 2008
ChemistryTutorsite.com-Chemistry Homework Help
A sample of 0.600 mol of metal M reacts completely with excess fluorine to form 46.8 gms of MF2 a) how many ?moles of F are in the sample of MF2 that forms? b) how many gms of M are in this sample of MF2? c) what element is represented by the symbol M?
ChemistryTutorsite.com-Chemistry Homework Answer
The chemical reaction between M and F2 can be written as:
M + F2 -> MF2
from the reaction above we know that 1 mole of M will be react completely with 1 mole of F2 to produce 1 mol of MF2 ( see the coefficient reaction). Thus 0.600 mol of M will be reacted with 0.600 mol of F2 to produce 0.600 of MF2.
thus the mass of F2
= mole x Mr
= 0.600 x 38
= 22.8 grams
thus the mass of M in the MF2
= mass of MF2 - mass of F2
= 46.8 - 22.8
= 24 gr
Mr of M can be calculate as:
mole = mass/Ar
Ar = mas/mol
Ar = 24/0.600
Ar = 40
when you check in the periodic table you will find that the atom that has Ar 40 is Ca
Entry Filed under: Stoichiometry
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