Calculate Molar Mass of A Gas Using Ideal Gas Law
Ideal gas law is an equation of state for a gas. This means that the state of the gas is its condition at a given time. It is important to recognize that the ideal gas law is an empirical equation that based on experimental measurements. The gas that obey this ideal gas law is said to behave ideally. However most gas obey the ideal gas law equation closely enough at pressure below 1 atm that only minimal errors result from assuming ideal behavior. A particular state of the gas is described by its pressure, volume, temperature, and number of moles. The knowledge of any three of these properties is enough to define the state of the gas, since the fourth property can be determined from the equation.
Here is the example how we calculate the molar mass of the gas using ideal gas law:
“What is the molecular mass of a gas if a volume of 500 cm3 has a mass of 1.00 g at -250C and 98.4 KPa?”
use the ideal gas law formula
in which:
P = Pressure in atm
V = Volume in Liter
n = mol
R = universal gas constant 0.08206 L.atm/K.mol
T = Temperature in K
First change the unit of all of the formula above
1 atm = 101325 Pa , so
P = 98.4 KPa = 98400 Pa
P = 98400 Pa/101325 Pa x 1 atm = 0.971 atm
V = 500 cm3 = 500 mL = 0.5 L
T = (-25) + 273 = 248 K
and substitute to the ideal gas law we have
0.971 atm x 0.5 L = n x 0.08206 L.atm/K.mol x 248 K
n = 0.024 mol
we know that mol = mass / Mr , thus
Mr = mass/mol
Mr = 1 / 0.024
Mr = 41.667
Mr = 42
thus the molecular mass of the gas is 42 gr/mol
Add comment June 8th, 2008