How to convert 40 mL CH3COOH to grams in diferent problems ?
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- How many grams of CH3COOH in the 40 mL of vinegar if the density of vinegar is 0.96 g/mL ?
- How many grams of CH3COOH in the 5 M of 40 mL of CH3COOH solution ?
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This is very easy to solve because the density of the vinegar has been known. To calculate the mass of the acetic acid we just multiply the volume of the vinegar with its density, and we get:
Mass of acetic acid = volume x density
Mass of acetic acid = 40 mL x 0.96 g/mL
Mass of acetic acid = 38.4 grams
In the second problem we have the volume and the molarity of the acetic acid solution. Since 1 Molar is one mole in the 1 liter of the solution, so we have 5 moles of acetic acid in the 1 liter of the solution. But in this problem we only have 40 mL of the solution, thus the moles are:
moles of acetic acid = Molarity x Volume
moles of acetic acid = 5 M x 0.04 L
moles of acetic acid = 0.2 moles
and the mass of acetic acid in the 40 mL of 5 M acetic acid solution,
mass = moles x molar mass
mass = 0.2 mol x 60 g/mol
mass = 12 grams
Add comment May 26th, 2008