Calculate of Volume H2SO4 that Neutralize 200 grams of NaOH

April 26th, 2008

Chemistry Tutor Problem
What volume of 2.50 N H2SO4 is needed to neutralize 200 grams of NaOH? How would I write the equation? Would it be 2H20 + Na2SO4?

Chemistry Tutor - Solution

Using the titration formula you can easily solve this problem. First you need to convert the 200 g of NaOH into its moles after that substituting the moles into the titration formula you will get the moles of H2SO4 that needed to neutralized the NaOH. To convert the moles of H2SO4 into volume you just need to use the molarity equation. See the way to solve this problem:

NV acid = NV base or
NV (H2SO4) = n x M x V NaOH
NV (H2SO4) = n x mol / V x V (NaOH)
V (H2SO4) = ( n x mol ) NaOH / N H2S)4

The moles of NaOH
= g / Molar Mass
= 200 / 39.998
= 5.000 mol

V (H2SO4) = ( n x mol ) NaOH / N H2S)4
V (H2SO4) = ( 1 x 5.000 ) / 2.50 N
V (H2SO4) = 2.000 L

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